SSC CGL 202021)Amit borrowed a sum of Rs. 25,000 on simple interest. Bhola borrowed the same amount on compound interest (interest compounded yearly). At the end of 2 years, Bhola had to pay Rs. 160 more interest than Amit. The rate of interest charged per annum is:
8%
For 2 years, Difference between C.I. and S.I. = \(P({R\over100})^2\); ⇒ \(160 = 25000\times({R\over100})^2\); ⇒ R = 8% per annum
SSC CGL 202022)What will be the difference in compound interest on a sum of Rs. 7,800 at 8% p.a. for 1 year, when the interest is paid yearly and half yearly?
Rs. 12.48
For 1 year, C.I. = S.I.; Here, interest = R = 4% per half year; For 2 half-years, C.I. - S.I. = \({PR^2\over10000}= {7800\times4\times4\over10000}\) = Rs. 12.48
SSC CGL 202023)A certain amount of money at compound interest grows to Rs. 66,550 in 3 years and Rs. 73,205 in 4 years. The rate percent per annum is:
10%
Difference in the interest in 4 years and 3 years = 73205 - 66550 = Rs.6655;
Rate percentage = \({6655\over66550}\times100\) = 10%
SSC CGL 201624)A trader sold a cycle at a loss of 10%. If the selling price had been increased by Rs. 200, there would have been a gain of 6%. The cost price of the cycle is
Rs.1250
SSC CGL 201625)The simple interest on a sum for 5 years is two-fifth of the sum. The rate of interest per annum is
0.08
SSC CGL 202026)A and B together borrowed a sum of Rs. 51,750 at an interest rate of 7% p.a. compound interest in such a way that to settle the loan, A paid as much amount after three years as paid by B after 4 years from the day of borrowing. The sum (in Rs.) borrowed by B was:
25,000
Let A borrow be Rs.x.
Borrowed by B = 51,750 - x;
Compound interest rate(r) = 7%;
Amount paid by A after 3 year = amount paid by B after 4 year;
Amount = \(principal(1 + r/100)^t\); ⇒ \(x(1 + 7/100)^3 = (51, 750 − x)(1 + 7/100)^4\) ; ⇒ \(x = (51, 750 − x) × 107/100\) ; ⇒ 100x = 5537250 - 107x ; ⇒ x = 5537250/207 = 26750;
Borrowed by B = 51,750 - x = 51,750 - 26750 = 25000
SSC CGL 202027)The compound interest on a certain sum at \(16\frac{2}{3}\)% p.a. for 3 years is Rs. 6,350. What will be the simple interest on the same sum at the same rate for \(5\frac{2}{3}\) years?
Rs. 10,200
Compound interest = 6350; Rate(r) =\( 16\frac{2}{3}\)% = (50/3)%; Time(t) = 3 years;
Compound interest = \( p[(1 + \frac{r}{100})^t - 1]\)
\(6350 = p(1 + \frac{50/3}{100})^3 - 1\) ; ⇒ p = 10800;
Simple interest = \(\frac{prt}{100}\)
r = (50/3)% ; t =\( 5\frac{2}{3}\) = 17/3 ;
Simple interest = \( \frac{10800 \times (50/3) \times (17/3)}{100}\) = Rs.10200
SSC CHSL 202128)Anamika paid Rs. 4,965 as compound interest on a loan of Rs. 15,000 after 3 years when compounded annually. Suman took a loan of Rs. 10,000 at the same rate on simple interest. How much interest did Suman pay after 3 years?
Rs. 3000
SSC CHSL 202129)The compound interest (in Rs., to the nearest integer) on Rs.8,950 for 2 years at the rate of 9% per annum, compounded annually, is:
1,683
SSC CHSL 202130)The simple interest on a certain sum for 3 years at 12% p.a. is Rs.6,750. What is the compound interest (in Rs.) on the same sum for 2 years at 20% p.a., if interest is compounded half-yearly? (rounded off to the nearest Rs.)
8,702