SSC CGL Mains 20241)Find the median of the following data. (Rounded off to 2 decimal places.)
Class interval 0-5 5-10 10-15 15-20 20-25 25-30 30-35
Frequency 3 5 4 2 7 6 5
21.43
SSC CGL Mains 20242)Anil and Beena are friends, and the difference between their ages is 5 years. Anil’s father Dinesh is three times as old as Anil, and Beena is twice as old as her sister Charu. The ages of Dinesh and Charu differ by 45 years. If Beena is older than Anil, then find the sum of the present ages of both Dinesh and Charu.
69 years
SSC CGL Mains 20243)Using empirical formula, calculate the mode for the following data.17, 20, 21, 18, 25, 28, 24, 22, 16, 24, 25, 24
25
SSC CGL Mains 20244)Let A and B be two players who are playing the game to hit the target. The probabilities of hitting the target by A and B is 2/3 and 3/4, respectively. What is the probability that exactly one of them hit the target?
5/12
SSC CGL Mains 20245)The age of some students is given in years as 12, 13, 16, 18,14, 19, 13, 17, 15 and 11. The median age (in years) of the students is:
14.5
SSC CGL Mains 20246)![]()
Independent
SSC CGL Mains 20247)Find the median of the following data.
Class interval 0 – 20 20 – 40 40 – 60 60 – 80 80 - 100
Frequency 9 16 24 15 4
47.5
SSC CGL Mains 20248)Adi and Dia together have ₹1,440. If of Adi's amount is equal to of Dia's amount, how much amount does Dia have?
₹480
SSC CGL 20229)A truck runs 492 km on 36 Litter of diesel. How many kilometres can it run on 33 Litter of diesel?
451 km
10)500 soldiers in a fort had enough food for 30 days but 125 soldiers were transferred to another fort. For how many days did the food last then?
40 days
SSC CGL 201611)If l + m + n = 9 and l2 + m2 + n2 = 31, then the value of lm + mn + nl will be
25
SSC CGL 201912)The value of \({7+8 \times8 \div8 of 8+8\div8\times4 of 4}\over{4\div4 of 4+4\times4\div4-4\div4 of 2}\) is :
6.4
\({7+8 \times8 \div8 of 8+8\div8\times4 of 4}\over{4\div4 of 4+4\times4\div4-4\div4 of 2}\);
On solving by the BODMAS rule,
\(7+{8\times8\over8\times8}+8\times{1\over8}\times16\over4\div16+4-4\times{1\over8}\) = \(7+1+16\over{1\over4}+4-{1\over2}\) = \(24\over{1+16-2\over4}\) = \(32\over5\) =6.4