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objective Ques (105 results)
1)

The value of 1800/20 x {(12-6) + (24-12)} is

SSC CGL 2020
A)

2720

B)

840

C)

1720

D)

1620

2)

The value of \({22.\bar{4}+11.5\bar{67}-33.5\bar{9}}\) is :

SSC CGL 2019
A)

\({0.\bar{32}}\)

B)

\({0.\bar{412}}\)

C)

\({0.3\bar{1}}\)

D)

\({0.4\bar{12}}\)

3)

The value of \(\left(2\frac{6}{7}of4\frac{1}{5}\div\frac{2}{3}\right)\times\)\(1\frac{1}{9}\div\)\(\left(\frac{3}{4}\times2\frac{2}{3}of\frac{1} {2}\div\frac{1}{4}\right)\) is :

SSC CGL 2019
A)

5

B)

8

C)

\(1\over8\)

D)

\(1\over5\)

4)

The value of \(\sqrt{28+10\sqrt3}-\)\(\sqrt{7-4\sqrt3}\) is closest to :

SSC CGL 2019
A)

7.2

B)

6.1

C)

6.5

D)

5.8

5)

The value of \(0.4\bar7+0.5\bar{03}-0.3\bar9\times0.\bar8\) is :

SSC CGL 2019
A)

\(0.6\bar{15}\)

B)

\(0.\bar{615}\)

C)

\(0.62\bar5\)

D)

\(0.6\bar{25}\)

6)

The value of \(24\times2\div12\)\(+12\div6\space of\space2\div\)\((15\div8\times4)\space of\)\(\space(28\div7\space of\space5)\) is :

SSC CGL 2019
A)

\(4\frac{1}{6}\)

B)

\(4\frac{8}{75}\)

C)

\(4\frac{2}{3}\)

D)

\(4\frac{32}{75}\)

7)

A student was asked to find the value of \(9\frac{4}{9}\div11\frac{1}{3}\space of\space\frac{1}{6}+\)\((1\frac{1}{3}\times1\frac{4}{5}\div\frac{3}{5})\)\(\times2\frac{1}{6}\space of\space \frac{2}{3}\)\(\div\frac{4}{3}\space of\space \frac{2}{3}\). His answer was \(19\frac{1}{4}\). What is the difference between his answer and the correct answer?

SSC CGL 2019
A)

\(7\frac{3}{4}\)

B)

\(6\frac{2}{3}\)

C)

\(7\frac{1}{2}\)

D)

\(6\frac{1}{3}\)

8)

The value of \((4.6)^4+(5.4)^4+(24.84)^2\over(4.6)^2+(5.4)^2+24.84\) is :

SSC CGL 2019
A)

24.42

B)

24.24

C)

25.42

D)

25.48

9)

The value of \((1\frac{1}{3}\div2\frac{6}{7}\space of\space5\frac{3}{5})\div\)\((6\frac{2}{5}\div4\frac{1}{2}\space of\space5\frac{1}{3})\times\)\(({3\over4}\times2\frac{2}{3}\)\(\div{5\over9}\space of\space 1\frac{1}{5})\)\(=1+k,\) where k lies between :

SSC CGL 2019
A)

-0.07 and -0.06

B)

-0.08 and -0.07

C)

-0.06 and -0.05

D)

-0.05 and -0.04

10)

The expression \(\sqrt{10+2(\sqrt6-\sqrt{15}-\sqrt{10})}\) is equal to :

SSC CGL 2019
A)

\(\sqrt3+\sqrt2-\sqrt5\)

B)

\(\sqrt3-\sqrt2-\sqrt5\)

C)

\(\sqrt3-\sqrt2+\sqrt5\)

D)

\(\sqrt2-\sqrt3-\sqrt5\)

showing 1 - 10 results of 105 results

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