SSC CGL 202011)Solve the following.
\({4\over3}\div{1\over6}\times2-1 = ?\)
15
\({4\over3}\div{1\over6}\times2-1 = {4\over3}\times{6}\times2-1 = 15\)
SSC CGL 202012)The value of \(-1+{1\over4}\div{1\over2}\times2+5\) is :
5
SSC CGL 202013)The value of \(\frac{3}{5} \times 1 \frac{7}{8} \div 1\frac{1}{3} of \frac{3}{16} - \left(3 \frac{1}{5} \div 4 \frac{1}{2} of 5 \frac{1}{3}\right) \times 2\frac{1}{2} + \frac{1}{2} + \frac{1}{8} \div \frac{1}{4}\) is:
\(4 \frac{5}{12}\)
SSC CGL 202014)The value of \(\frac{3\frac{2}{3} \div \frac{11}{30} \space of \space \frac{2}{3} - \frac{1}{4} \space of \space 2\frac{1}{2} \div \frac{3}{5} \times 4 \frac{4}{5}} {\frac{2}{5} \space of \space 7\frac{1}{2} \div \frac{3}{4} - \frac{3}{4} \times 1\frac{1}{2} \div 2\frac{1}{4}}\) is:
\(2{6\over7}\)