SSC CGL 201911)If x is the remainder when \(3^{61284}\) is divided by 5 and y is the remainder when \(4^{96}\) is divided by 6, then what is the value of \((2x-y)\) ?

Correct Option: C

-2

x is the remainder when \(3^{61284}\) is divided by 5; So, \({3^{61284}\over5}={3^{4\times15321}\over5}\) ; \({3^4\over5}={81\over5}\); Remainder = 1; x=1;

y is the remainder when \(4^{96}\) is divided by 6; remainder is always '4'; thereforey = 4.

2x-y = 2-4 = -2

SSC CGL 201912)The value of \(\sqrt{28+10\sqrt3}-\)\(\sqrt{7-4\sqrt3}\) is closest to :

Correct Option: C

6.5

\(\sqrt{28+10\sqrt3}-\sqrt{7-4\sqrt3}\) = \(\sqrt{(5)^2+(\sqrt3)^2+2\times5\sqrt3}-\sqrt{(2)^2+(\sqrt3)^2-2\times2\sqrt3}\) =\(\sqrt{(5+\sqrt3)^2}-\sqrt{(2-\sqrt3)^2}=6.464\)

SSC CGL 201913)The value of \(0.4\bar7+0.5\bar{03}-0.3\bar9\times0.\bar8\) is :

Correct Option: D

\(0.6\bar{25}\)

SSC CGL 201914)The LCM of two numbers x and y is 204 times their HCF. If their HCF is 12 and the difference between the numbers is 60, then x + y = ?

Correct Option: D

348

SSC CGL 201915)The value of \(24\times2\div12\)\(+12\div6\space of\space2\div\)\((15\div8\times4)\space of\)\(\space(28\div7\space of\space5)\) is :

Correct Option: A

\(4\frac{1}{6}\)

SSC CGL 201916)In finding the HCF of two numbers by division method, the last divisor is 17 and the quotients are 1. 11 and 2, respectively. What is sum of the two numbers?

Correct Option: C

816

SSC CGL 201917)A student was asked to find the value of \(9\frac{4}{9}\div11\frac{1}{3}\space of\space\frac{1}{6}+\)\((1\frac{1}{3}\times1\frac{4}{5}\div\frac{3}{5})\)\(\times2\frac{1}{6}\space of\space \frac{2}{3}\)\(\div\frac{4}{3}\space of\space \frac{2}{3}\). His answer was \(19\frac{1}{4}\). What is the difference between his answer and the correct answer?

Correct Option: A

\(7\frac{3}{4}\)

SSC CGL 201918)If a 10-digit number 5 4 3 2 y 1 7 4 9 x is divisible by 72, then what is the value of (5x - 4y)?

Correct Option: A

14

SSC CGL 201919)What is the remainder when \((127^{97}+97^{97})\) is divided by 32?

Correct Option: D

0

SSC CGL 201920)Two positive numbers differ by 2001, When the larger number is divided by the smaller number, the quotient is 9 and the remainder is 41. The sum of the digits of the larger number is:

Correct Option: D

14

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