SSC CGL 201921)A is 25% more than B and B is 40% less than C. If C is 30% more than D, then by what percent is A less than D?
2.5
Let B be 100, then A will be 125 ;
Now; \( {60 \over 100}C = 100 \) then; \(C = {500\over 3}\) ;
Also, \({130\over 100}D = C = {500\over 3}\) ; then \(D= {5000 \over 3 \times 13}\) ;
\({A \over D } \times 100 = {125 \times 3 \times 13\over 5000}\times 100= {195\over 2}\)%
Since we have to calculate less than percentage it will be \(100-{195\over 2} = 2.5\) %
SSC CGL 202022)The price of cooking oil increased by 25%. Find by how much percentage a family must reduce its consumption in order to maintain the same budget?
20%
By the formula,
Decrements in the consumption in order to maintain the same budget =\( \frac{increment in the rate}{100 + increment in the rate} \times 100\)= \(\frac{25}{100 + 25} \times 100 = \frac{25}{125} \times 100 \)= 20%
SSC CGL 202023)A car dealer purchased an old car for Rs.1,08,500 and spent some amount on its maintenance. He sold it for Rs.1,56,250, there by earning a profit of 25%. How much money did he spend on the maintenance of the car?
Rs. 16,500
Total cost price of old car = 1,08,500 + maintenance money;
Selling price = 1,56,250;
Profit = 25%;
Total cost price = \(\frac{156250}{125} \times 100\) = 125000;
1,08,500 + maintenance money = 125000;
Maintenance money = 125000 - 108500 = Rs. 16,500
SSC CGL 202024)When two equal amounts are deposited for 5 years and 3 years at the rate of 7% and 9% per annum respectively, and the difference of their simple interest is Rs 475. Then find the deposited amount.
Rs. 5,937.5
Difference of the interest = 475;
\(\frac{p \times 7 \times 5}{100} - \frac{p \times 9 \times 3}{100}\) = 475;
35p - 27p = 47500;
p = 47500/8 = Rs. 5937.5
SSC CGL 202025)By what number must the given number be multiplied to increase the number by 25%.
\(5\over4\)
Number to increase 25% = 125% = 125/100 = 5/4
SSC CGL 202026)If the radius of a circle is decreased by 11%, then the total decrease in the area of the circle is given as:
20.79%
Old radius be 'r' and old area = \(\pi r^2\); then new radius = \(89r\over100\); new area = \(\pi({89r\over100})^2\);
Change in area % = \({\pi({89r\over100})^2-\pi r^2\over\pi r^2}\times100\) = - 20.79%
SSC CGL 202027)Anu spends 68% of her monthly income. If her monthly income increases by 20% and her monthly savings increase by \(9{3\over8}\)%, then the percentage increase in her monthly expenditure is:
25%
Anu's monthly income = Rs. 100; Her expenses = Rs. 68; Her saving = Rs.(100-68) = Rs. 32; Her new income = Rs. 120 ;
Her saving = \((32+32\times{75\over8\times100})\) = Rs. 35; Her epenses = (120 - 35) = Rs. 85;
Percentage increase in expenses = \(({85-68\over68})\times100\) = 25%
SSC CGL 202028)In an examination, Anita scored 31% marks and failed by 16 marks. Sunita scored 40% marks and obtained 56 marks more than those required to pass. Find the minimum marks required to pass.
264
Equate passing mark obtained by the students . Let total marks be x. then,\({31x\over100}+16={40x\over100}-56\); x = 800; So passing marks = \({31\times800\over100}+16 =264\)
SSC CGL 202029)In a school, 4 % of the students did not appear for the annual exams. 10% of the students who appeared for the exams could not pass the exam. Out of the remaining students, 50% got distinction marks and 432 students passed the exam but could not get distinction marks. The total number of students in the school is:
1000
Let total number of students be x. According to the question, 50%of 90% of 96% of x = 432 ; ⇒ x = 1000
SSC CGL 202030)The price of sugar is increased by 20%. By what percentage must one cut down on the consumption of sugar, so that no extra amount has to be incurred on sugar?
\(16{2\over3}\)%
Required percent = \({20\over100+20}\times100 = 16{2\over3}\)%