SSC CGL 201921)A solid cylinder of base radius 12 cm and height 15 cm is melted and recast into n toys each in the shape of a right circular cone of height 9 cm mounted on a hemisphere of radius 3 cm. The value of n is:
48
SSC CGL 201922)The internal diameter of a hollow hemispherical vessel is 24 cm. It is made of a steel sheet which is 0.5 cm thick, What is the total surface area (in \(cm^2\)) of the vessel?
\(612.75\pi\)
SSC CGL 201923)A sector of radius 10.5 cm with the central angle \(120^0\) is folded to form a cone by joining the two bounding radii of the sector. What is the volume (in \(cm^3\)) of the cone so formed?
\({343\sqrt2\over12}\pi\)
Radius of sector r = 10.5 cm
Circumference of sector whose angle is 120° = 2 πr × (θ/360) = 2 × (22/7) × 10.5 × (120/360) = 22cm
If we make cone from sector then,
Slant height (l) of the cone = radius of sector = 10.5 cm
Circumference of the cone = 22
2πr = 22, where r is the radius of cone
⇒ 2 × (22/7) × r = 22
⇒ r = 7/2 = 3.5 cm
As we know,
⇒ l2 = r2 + h2
⇒ (10.5)2 = (3.5)2 + h2
⇒ h2 = 110.25 – 12.25
⇒ h = 7 √2 cm
SSC CGL 201924)The area of the base of a right circular cone is \(400\pi\) and its height is 15 cm. The curved surface area of the cone (in \(cm^2\)) is:
\(500\pi\)
SSC CGL 201925)The base of a right prism is a triangle with sides 20 cm, 21 cm and 29 cm. If its volume is 7560 \(cm^3\), then its lateral surface area (in \(cm^2\)) is:
2520
SSC CGL 201926)A cylindrical vessel of radius 3.5 m is full of water. If 15400 litres of water is taken out from it, then the drop in the water level in the vessel will be:
40 cm
SSC CGL 201927)A solid metallic sphere of radius 8 cm is melted and drawn into a wire of uniform cross-section. If the length of the wire is 24 m, then its radius (in mm) is:
\(5\frac{1}{3}\)
SSC CGL 201928)The base of a right pyramid is an equilateral triangle with side 8 cm, and the height of the pyramid is \(24\sqrt3\) cm. The volume (in \(cm^3\)) of the pyramid is:
384
Volume of pyramid = (1/3) × Area of base × height
The base of a right pyramid is an equilateral triangle with side 8 cm, and the height of the pyramid is 24√3 cm.
Volume = (1/3) × (√3/4) × 82 × 24√3
⇒ 384 cm3
SSC CGL 201929)If the diameter of the base of a right circular cylinder is reduced by \(33\frac{1}{3}\)% and its height is doubled, then the volume of the cylinder will :
decrease by \(11\frac{1}{9}\)%
SSC CGL 201930)A right circular solid cone of radius 3.2 cm and height 7.2 cm is melted and recast into a right circular cylinder of height 9.6 cm. What is the diameter of the base of the cylinder?
3.2 cm.