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A tank is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the tank in the same time during which the tank is filled by the third pipe alone. The second pipe fills the tank 5 hours faster than the first pipe and 4 hours slower than the third pipe. The time required by the first pipe is:Watch Solution
A and B can complete a certain task in 24 days and 40 days, respectively. They worked together for 8 days. C completed the remaining task in 14 days. Working together, A and C will complete 75% of the same work in:Watch Solution
Three taps A, B and C can fill a tank in 12, 15 and 20 hours respectively. If A is open all the time and B and C are open for one hour each alternately, the tank will be full in:Watch Solution
X, Y and Z can do a piece of work in 46 days, 92 days and 23 days, respectively, X started the work. Y joined him after 2 days. If Z joined them after 8 days from the beginning then for how many days did X work?Watch Solution
Pipe A and Pipe B can alone fill a tank in 20 hours and 30 hours, respectively and Pipe C alone can empty the tank in 15 hours. If pipe A opened alone for the first hour and Pipe B opened alone for the second hour and after the second hour all three pipes are opened, then the total time required to fill the tank is –Watch Solution