Class 10 Maths1)The prime factors of 196 are

Correct Option: A

\(2^2 \times 7^2\)

Class 10 Maths2)

The decimal expansion of \(\frac{{987}}{{10500}}\)will terminate after:

Correct Option: A

3 decimal places

Class 10 Maths3)For every positive integer n,\(n^2\) - n is divisible by

Correct Option: D

2

\(n^2 \)- n = n(n - 1). Since n and (n - 1) are consecutive integers. Therefore, one of them must be divisible by 2.

Class 10 Maths4)The HCF of two consecutive numbers is

Correct Option: B

1

The HCF of two consecutive numbers is always 1. ( e.g. HCF of 24, 25 is 1).

Class 10 Maths5)A number when divided by 143 leaves 31 as remainder. What will be the remainder when the same number is divided by 13?

Correct Option: E

5

Class 10 Maths6)120 can be expressed as a product of its prime factors as:

Correct Option: C

\(5 × 2^3 × 3\)

\(120 = 5 × 2^3 × 3\)

Class 10 Maths7)

The product of two numbers is 1600 and their HCF is 5. The LCM of the numbers is

Correct Option: C

320

Class 10 Maths8)By Euclid’s division lemma x = qy + r, x > y the value of q and r for x = 27 and y = 5 are:

Correct Option: A

q = 5, r = 2

x = qy + r

27 = 5 ×× 5 + 2

q = 5, r = 2

Class 10 Maths9)The decimal expansion of \(23 \over 2^5×5^2 \) will terminate after how many places of decimal?

Correct Option: B

5

Class 10 Maths10)HCF of 144 and 198 is:

Correct Option: C

18

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